/** If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000. */

#include "0.hpp"

const int _a = 3;
const int _b = 5;
const int _max = 1000;

int main()
{
  int total = 0;
  for(int i = 1; i < 1000; i++) // 循环体
    if(i % _a == 0 || i % _b == 0) total += i; // 满足条件的数字加入到 total 中
  cout << total << endl;
  return 0;
}