from math import log10
sq2 = [(1, 1)]
count = 0
for i in xrange(1, 1001):
  last = sq2[len(sq2) - 1]
  if int(log10(last[0])) > int(log10(last[1])):
    print last
    count += 1
  sq2.append((last[0] + 2 * last[1], last[0] + last[1]))
print count