19 lines
410 B
Python
19 lines
410 B
Python
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weekday = [5]
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month = (31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30)
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def leap_day(year):
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if not (year % 400):
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return 1
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if (year % 100) and (not (year % 4)):
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return 1
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return 0
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for y in range(1900, 2001):
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for m in month:
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weekday.append((weekday[-1] + m) % 7)
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if 28 == m:
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weekday[-1] = (weekday[-1] + leap_day(y)) % 7
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print(weekday[13:].count(0))
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