58 lines
1.7 KiB
C++
58 lines
1.7 KiB
C++
/** If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
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If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?
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NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance with British usage. */
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#include "0.hpp"
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int ele[20] = {0, 3, 3, 5, 4, 4, 3, 5, 5, 4, 3,
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6, 6, 8, 8, 7, 7, 9, 8, 8};
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int ten[11] = {0, 3, 6, 6, 5, 5, 5, 7, 6, 6, 7};
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int dot[4] = {0, 8, 7, 7};
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string eles[20] = {"", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
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string tens[11] = {"", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "nithty", "hundrad"};
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string dots[4] = {"", "thousand", "million", "billion"};
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int analyse(int x)
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{
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int a = x / 100;
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int b = x % 100;
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int out = 0;
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if(a) {
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if(a / 10) {
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out += ele[a / 10] + dot[1]; // thousand
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cout << eles[a / 10] + " " + dots[1] + " ";
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}
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if(a % 10) {
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out += ele[a % 10] + ten[10]; // hundrad
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cout << eles[a % 10] + " " + tens[10] + " ";
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}
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if(b) {
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out += 3; // and
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cout << "and ";
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}
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}
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if(b >= 20) {
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out += ele[b % 10] + ten[b / 10];
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cout << tens[b / 10] + " " + eles[b % 10] + " ";
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}
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else {
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out += ele[b];
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cout << eles[b];
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}
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cout << endl;
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return out;
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}
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int main()
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{
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int sum = 0;
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for(int i = 1; i <= 1000; i++) sum += analyse(i);
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cout << sum << endl;
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return 0;
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}
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