24 lines
735 B
C++
24 lines
735 B
C++
/** The sum of the squares of the first ten natural numbers is,
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1^2 + 2^2 + ... + 10^2 = 385
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The square of the sum of the first ten natural numbers is,
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(1 + 2 + ... + 10)^2 = 552 = 3025
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Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
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Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum. */
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#include "0.hpp"
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#define _max 100
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int main()
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{
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uu sum = 0; // 最终的和
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uu num[_max];
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for(int i = 0; i < _max; i++) num[i] = i + 1;
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for(int i = 0; i < _max; i++)
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for(int j = i + 1; j < _max; j++)
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sum += num[i] * num[j];
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sum *= 2;
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cout << sum << endl;
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return 0;
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}
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