20 lines
1.3 KiB
Python
20 lines
1.3 KiB
Python
# coding=utf-8
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''' Discover the largest product of five consecutive digits in the 1000-digit number. '''
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def va(string):
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x = 1
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for i in range(len(string)):
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x *= ord(string[i]) - ord('0')
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return x
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ch = '731671765313306249192251196744265747423553491949349698352031277450632623957831801698480186947885184385861560789112949495459501737958331952853208805511125406987471585238630507156932909632952274430435576689664895044524452316173185640309871112172238311362229893423380308135336276614282806444486645238749303589072962904915604407723907138105158593079608667017242712188399879790879227492190169972088809377665727333001053367881220235421809751254540594752243258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450'
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max = [0, 0, '']
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for i in range(len(ch) - 5):
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temp = va(ch[i : i + 5])
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if temp > max[1]:
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max[0] = i
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max[1] = temp
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max[2] = ch[i : i + 5]
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print max
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