29 lines
551 B
C++
29 lines
551 B
C++
/** n! means n * (n - 1) * ... * 3 * 2 * 1
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For example, 10! = 10 * 9 * ... * 3 * 2 * 1 = 3628800,
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and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
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Find the sum of the digits in the number 100! */
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#include "0.hpp"
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#include "lib/lint.cpp"
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#define _max 100
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uint sum(string a)
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{
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uint suma = 0;
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for(uint i = 0; i < a.size(); i++) suma += (a[i] - '0');
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return suma;
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}
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int main()
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{
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lint a("1");
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lint b;
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for(int i = 1; i <= _max; i++) {
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b = itos(i);
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a = a * b;
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}
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cout << sum(a.getd()) << endl;
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}
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