26 lines
540 B
Python
26 lines
540 B
Python
# coding=utf-8
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''' If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
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Find the sum of all the multiples of 3 or 5 below 1000. '''
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def calc(n, a):
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tmp = n / a
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return (tmp + 1) * tmp * a / 2
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x = 3
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y = 5
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maxx = 1000
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out = calc(maxx, x) + calc(maxx, y) - calc(maxx, x * y)
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print out
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'''
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total = 0
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for i in range(1000):
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if i % 3 == 0 or i % 5 == 0: # 条件为能被 3 或 5 整除
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total += i # 足条件的数字加入到 total 中
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print total
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'''
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