11 lines
248 B
Python
11 lines
248 B
Python
from math import log10
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sq2 = [(1, 1)]
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count = 0
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for i in xrange(1, 1001):
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last = sq2[len(sq2) - 1]
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if int(log10(last[0])) > int(log10(last[1])):
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print last
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count += 1
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sq2.append((last[0] + 2 * last[1], last[0] + last[1]))
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print count
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