17 lines
618 B
Python
17 lines
618 B
Python
# coding=utf-8
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''' The sum of the squares of the first ten natural numbers is,
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1^2 + 2^2 + ... + 10^2 = 385
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The square of the sum of the first ten natural numbers is,
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(1 + 2 + ... + 10)^2 = 552 = 3025
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Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
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Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum. '''
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total = 0
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num = []
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for i in range(100): num.append(i + 1)
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for i in range(100):
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for j in range(i + 1, 100):
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total += num[i] * num[j]
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total *= 2
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print total
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